document.write( "Question 152127This question is from textbook elementary and intermediate algebra
\n" );
document.write( ": solve for 'a'
\n" );
document.write( "3a=c-a(b+d)\r
\n" );
document.write( "\n" );
document.write( "answer is a=c/3+b+d\r
\n" );
document.write( "\n" );
document.write( "with a negative 'a', how do you get to the single 'a' on the right?
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #111819 by vleith(2983) ![]() You can put this solution on YOUR website! Given \n" ); document.write( "First use distribution to expand the right side \n" ); document.write( " \n" ); document.write( "Now move all the terms with an 'a' in them to the same side \n" ); document.write( " \n" ); document.write( "Now use distribution to pull the a out of the three terms on the left side \n" ); document.write( " \n" ); document.write( "Now divide both sides by (3+b+d) \n" ); document.write( " |