document.write( "Question 152127This question is from textbook elementary and intermediate algebra
\n" ); document.write( ": solve for 'a'
\n" ); document.write( "3a=c-a(b+d)\r
\n" ); document.write( "\n" ); document.write( "answer is a=c/3+b+d\r
\n" ); document.write( "\n" ); document.write( "with a negative 'a', how do you get to the single 'a' on the right?
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Algebra.Com's Answer #111819 by vleith(2983)\"\" \"About 
You can put this solution on YOUR website!
Given \"3a=c-a%28b%2Bd%29\"
\n" ); document.write( "First use distribution to expand the right side
\n" ); document.write( "\"3a=c-ab+-ad\"
\n" ); document.write( "Now move all the terms with an 'a' in them to the same side
\n" ); document.write( "\"3a+%2B+ab+%2B+ad+=+c\" Basically we added ab+ad to both sides
\n" ); document.write( "Now use distribution to pull the a out of the three terms on the left side
\n" ); document.write( "\"a%2A%283%2Bb%2Bd%29+=+c\"
\n" ); document.write( "Now divide both sides by (3+b+d)
\n" ); document.write( "\"a+=+c+%2F+%283%2Bb%2Bd%29\"
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