document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151995>Question 151995</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle is twice as long as it is wide.  If its length is decreased by 4 and its width is decreased by 2, its area is decreased by 32.  Find the original dimensions. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111818 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose its width is x, then its length is 2x.<BR>\n" );
document.write( "So its area is 2x^2.<BR>\n" );
document.write( "The new rectangle's width is x + 2, length is 2x + 4, so its area is (x+2)(2x+4).<BR>\n" );
document.write( "As the area of new rectangle is 32 more than the original one, we have<BR>\n" );
document.write( "(x+2)(2x+4) = 2x^2 + 32\r<BR>\n" );
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document.write( "To Solve the equation for x, first we simplify it by dividing both sides by 2.<BR>\n" );
document.write( "(x+2)(x+2) = x^2 + 16<BR>\n" );
document.write( "Or written as<BR>\n" );
document.write( "(x+2)^2 = x^2 + 16<BR>\n" );
document.write( "Expanding the left side, we have<BR>\n" );
document.write( "x^2 + 4x + 4 = x^2 + 16<BR>\n" );
document.write( "4x = 12<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "So the dimensions of the original rectangle is 3 and 6.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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