document.write( "Question 151989: A passenger train's speed is 60mi/h, and a freight train's speed is 40mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip? \n" ); document.write( "
Algebra.Com's Answer #111812 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A passenger train's speed is 60mi/h, and a freight train's speed is 40mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?
\n" ); document.write( ":
\n" ); document.write( "Let t = freight train time
\n" ); document.write( "then
\n" ); document.write( "(t-1.5) = Passenger train time
\n" ); document.write( ";
\n" ); document.write( "Write a distance equation: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "Pass dist = Freight dist
\n" ); document.write( "60(t-1.5) = 40t
\n" ); document.write( "60t - 90 = 40t
\n" ); document.write( "60t - 40t = 90
\n" ); document.write( "20t = 90
\n" ); document.write( "t = \"90%2F20\"
\n" ); document.write( "t = 4.5 hrs for freight
\n" ); document.write( "and
\n" ); document.write( "4.5 - 15 = 3 hr for the passenger train
\n" ); document.write( ":
\n" ); document.write( "Check solution by confirming the dist on both trains
\n" ); document.write( "40 * 4.5 = 180 mi
\n" ); document.write( "60 * 3 = 180 mi \n" ); document.write( "
\n" );