document.write( "Question 21038: Melissa invested a sum of money at 3% annual simple interest. She invested three times that sum at 5% annual simple intrest. If her total yearly intrest from both investments was $3600, how much was invested at 3%? \n" ); document.write( "
Algebra.Com's Answer #11181 by stanbon(75887) ![]() You can put this solution on YOUR website! Let \"x\" be the amount invested at 3% \n" ); document.write( "Then \"3x\" is the amount invested at 5% \n" ); document.write( "Equation: \n" ); document.write( " 0.03x + 0.05(3x) = 3600 \n" ); document.write( " 3x + 15x = 360000 \n" ); document.write( " 18x = 360000 \n" ); document.write( " x = $20,000 (amount invested at 3%) \n" ); document.write( " 3x = $60,000 (amount invested at 5%)\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |