document.write( "Question 21038: Melissa invested a sum of money at 3% annual simple interest. She invested three times that sum at 5% annual simple intrest. If her total yearly intrest from both investments was $3600, how much was invested at 3%? \n" ); document.write( "
Algebra.Com's Answer #11181 by stanbon(75887)\"\" \"About 
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Let \"x\" be the amount invested at 3%
\n" ); document.write( "Then \"3x\" is the amount invested at 5%
\n" ); document.write( "Equation:
\n" ); document.write( " 0.03x + 0.05(3x) = 3600
\n" ); document.write( " 3x + 15x = 360000
\n" ); document.write( " 18x = 360000
\n" ); document.write( " x = $20,000 (amount invested at 3%)
\n" ); document.write( " 3x = $60,000 (amount invested at 5%)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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