document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=152066>Question 152066</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/1565771346/algebrahomeworkh>Algebra 1 An Incremental Development</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Factor by grouping: 6wy - 2xy + 9bw - 3bx </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111796 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The \"trick\", of course, is to group terms together so you can factor them:<BR>\n" );
document.write( "Looking at:<BR>\n" );
document.write( "6wy - 2xy + 9bw - 3bx<BR>\n" );
document.write( "You could group them thus:<BR>\n" );
document.write( "(6wy - 2xy) + (9bw - 3bx)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Now, for each group pull out the common factor:<BR>\n" );
document.write( "2y(3w - x) + 3b(3w - x)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Now, look for common factors for the entire expression:<BR>\n" );
document.write( "(3w - x)(2y + 3b)\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );