document.write( "Question 152079: I need help with this one question i have been stuck on for a few days now here it is.
\n" ); document.write( "A process of elimination.\r
\n" ); document.write( "\n" ); document.write( "6x+2/3y= 9
\n" ); document.write( "2x+2/3y= 7\r
\n" ); document.write( "\n" ); document.write( "i dont have a text book number because it is in a module book
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Algebra.Com's Answer #111786 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Solve:
\n" ); document.write( "\"6x%2B%282%2F3%29y+=+9\"
\n" ); document.write( "\"2x%2B%282%2F3%29y+=+7\" Subtract the second equation from the first equation to eliminate the y.
\n" ); document.write( "\"4x+=+2\" Divide both sides by 4.
\n" ); document.write( "\"x+=+1%2F2\" Now substitute this value of x into either of the two given equations to solve for y. The second equation will work nicely.
\n" ); document.write( "\"2%281%2F2%29%2B%282%2F3%29y+=+7\" Simplify.
\n" ); document.write( "\"1%2B%282%2F3%29y+=+7\" Subtract 1 from both sides.
\n" ); document.write( "\"%282%2F3%29y+=+6\" Multiply both sides by the multiplicative inverse of \"2%2F3\", that's \"3%2F2\"
\n" ); document.write( "\"%283%2F2%29%282%2F3%29y+=+6%283%2F2%29\"
\n" ); document.write( "\"y+=+9\"
\n" ); document.write( "The solution is: (1/2, 9)
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