document.write( "Question 22802: Please help me solve this problem. I have tried, but it seems like something is missing.\r
\n" ); document.write( "\n" ); document.write( "Rosa drives to Barnesville at 50 mph and returns by a road 5 miles longer at 40 mph. The return trip takes 15 minutes longer. How long is each road? \n" ); document.write( "
Algebra.Com's Answer #11177 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Distance = (rate in mph)(time in hrs.)
\n" ); document.write( "Data going to Barnesville:
\n" ); document.write( "Let distance = d; rate is 50mph; time is t
\n" ); document.write( "Data returning:
\n" ); document.write( " distance = d+5; rate is 40mph; time is (t+(1/4)
\n" ); document.write( "Equations
\n" ); document.write( " To Barnesville: d = 50t
\n" ); document.write( " From Barnesville: d+5 =40(t+(1/4))\r
\n" ); document.write( "\n" ); document.write( "Solve by substitution:
\n" ); document.write( " 50t + 5 = 40t+10
\n" ); document.write( " 10t = 5
\n" ); document.write( " t = 1/2
\n" ); document.write( "Solve for distance:
\n" ); document.write( " To Barnes: d = 50t = 50(1/2) = 25 miles
\n" ); document.write( " From Barnes: d+5 = 20 miles\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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