document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151996>Question 151996</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Lainey is 5 years old than her sister,mary.  In 2 years she will be twice as old as her.  What is their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111733 by </B><A HREF=/tutors/aboutme.mpl?userid=orca><B>orca(409)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=orca><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the age of Mary now. Then Lainey's age now is x + 5.<BR>\n" );
document.write( "In two years, Mary's age will be x + 2<BR>\n" );
document.write( "In two years, Lainey's age will be x + 5 + 2 = x + 7<BR>\n" );
document.write( "As in two years Lainey will be twice as old as mary will be, we have<BR>\n" );
document.write( "x + 7 = 2(x + 2)<BR>\n" );
document.write( "Solving for x, we have:<BR>\n" );
document.write( "x + 7 = 2x + 4<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "So Mary is 3 now and Lainey is 8 now.<BR>\n" );
document.write( " </SPAN>\n" );
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