document.write( "Question 151986: How would I solve \r
\n" ); document.write( "\n" ); document.write( "(z+2)^-(2/3) = 3\r
\n" ); document.write( "\n" ); document.write( "i dont know if this is easy to understand but the first equation is to the negative two thirds power. \n" ); document.write( "

Algebra.Com's Answer #111728 by Earlsdon(6294) $\"\"$ $\"About$

You can put this solution on YOUR website!
Solve for x:\r
\n" ); document.write( "\n" ); document.write( " $\"%28z%2B2%29%5E%28-2%2F3%29+=+3\"$ Raise both sides to the power of $\"%28-3%2F2%29\"$
\n" ); document.write( " $\"%28%28z%2B2%29%5E%28-2%2F3%29%29%5E%28-3%2F2%29+=+3%5E%28-3%2F2%29\"$ To the left side, apply the \"product rule for exponents\" $\"%28M%5Ea%29%5Eb+=+M%5E%28ab%29\"$
\n" ); document.write( " $\"%28z%2B2%29+=+3%5E%28-3%2F2%29\"$
\n" ); document.write( " $\"z%2B2+=+%281%29%2F%283%5E%283%2F2%29%29\"$ This is supposed to be: $\"1\"$ over $\"3%5E%283%2F2%29\"$ and $\"3%5E%283%2F2%29+=+sqrt%2827%29\"$
\n" ); document.write( " $\"z%2B2+=+1%2Fsqrt%2827%29\"$ Multiply top and bottom by $\"sqrt%2827%29\"$
\n" ); document.write( " $\"z%2B2+=+sqrt%2827%29%2F27\"$ Now subtract 2 from both sides.
\n" ); document.write( " $\"z+=+sqrt%2827%29%2F27+-+2\"$
\n" ); document.write( " $\"z+=+%28sqrt%2827%29-54%29%2F27\"$ \n" ); document.write( "

\n" );