document.write( "Question 22799: I do apolgize. I just submitted a problem but I guess I didn't write it correctly. I'm still very new at this. \r
\n" ); document.write( "\n" ); document.write( "the question is \r
\n" ); document.write( "\n" ); document.write( "4^(x+1)=64 the x+1 are in exponential form. Where appropriate, include approximations to the nearest thousandth. \r
\n" ); document.write( "\n" ); document.write( "Again thank you so much.
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Algebra.Com's Answer #11171 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
I'm going to assume you do not want to solve this problem
\n" ); document.write( "using logarithms. If you do the procedure is quite different.
\n" ); document.write( "Without using logs you proceed as follows.
\n" ); document.write( "Rewrite the equation as follows:
\n" ); document.write( " 4^(x+1) = 4^3
\n" ); document.write( "Then x+1 = 3
\n" ); document.write( " x = 4\r
\n" ); document.write( "\n" ); document.write( "Hope this helps.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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