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document.write( "
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document.write( "Find the critical values by\r\n" );
document.write( "setting each factor = 0\r\n" );
document.write( "\r\n" );
document.write( "
gives critical value
\r\n" );
document.write( "
gives critical value
\r\n" );
document.write( "\r\n" );
document.write( "Place those critical values on a number line:\r\n" );
document.write( "\r\n" );
document.write( "-----------o-----------------------------------o---------\r\n" );
document.write( " -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12 \r\n" );
document.write( "\r\n" );
document.write( "Choose a test value for x in the region left of -3.\r\n" );
document.write( "The easiest number to choose is -4. Substitute this\r\n" );
document.write( "value into either the original inequality or its \r\n" );
document.write( "factored form. I'll choose to substitute in the\r\n" );
document.write( "factored form, but it does not matter which you\r\n" );
document.write( "substitute
in:\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "This is false so we do not shade the region left of -3.\r\n" );
document.write( "\r\n" );
document.write( "So we still have only:\r\n" );
document.write( "\r\n" );
document.write( "-----------o-----------------------------------o---------\r\n" );
document.write( " -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Choose a test value for x in the region right of -3 but\r\n" );
document.write( "left of 9. The easiest number to choose is 0. Substitute \r\n" );
document.write( "this value into either the original inequality or its \r\n" );
document.write( "factored form. I'll choose to substitute in the\r\n" );
document.write( "factored form, but it does not matter which you\r\n" );
document.write( "substitute
in:\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "This is true so we shade the region right of -3 but left of 9.\r\n" );
document.write( "\r\n" );
document.write( "-----------o===================================o---------\r\n" );
document.write( " -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Choose a test value for x in the region right of 9.\r\n" );
document.write( "The easiest number to choose is 10. Substitute this\r\n" );
document.write( "value into either the original inequality or its \r\n" );
document.write( "factored form. I'll choose to substitute in the\r\n" );
document.write( "factored form, but it does not matter which you\r\n" );
document.write( "substitute
in:\r\n" );
document.write( "\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "
\r\n" );
document.write( "\r\n" );
document.write( "This is false so we do not shade the region right of 9.\r\n" );
document.write( "\r\n" );
document.write( "So we still have:\r\n" );
document.write( "\r\n" );
document.write( "-----------o===================================o---------\r\n" );
document.write( " -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12\r\n" );
document.write( "\r\n" );
document.write( "Since the inequality is <, rather than <, neither\r\n" );
document.write( "critical value is itself a solution.\r\n" );
document.write( "\r\n" );
document.write( "So the final number line graph is:\r\n" );
document.write( "\r\n" );
document.write( "-----------o===================================o---------\r\n" );
document.write( " -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9 10 11 12\r\n" );
document.write( " \r\n" );
document.write( "and the interval notation for that is (
,
).\r\n" );
document.write( "\r\n" );
document.write( "Edwin
\n" );
document.write( "