document.write( "Question 151899This question is from textbook Algebra 2
\n" ); document.write( ": 1.Jay's test scores were 78,80,95, and 81. He took his last test for the quarter on Friday. What must he get to maintain a B average (between 80 and 89)\r
\n" ); document.write( "\n" ); document.write( "2. Ernie's average after 3 tests is at least 72%. If two of his test scores were 55 & 85, what could he have scored on his 3rd test?\r
\n" ); document.write( "\n" ); document.write( "3.Marissa has a square patio. She hires Ben to make it bigger. Ben uses 1'x1' tiles and increases the patio length 6' and doubles the patio's width. if the perimeter o the new patio is between 30' and 45', what could the dimensions of the original patio be?\r
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Algebra.Com's Answer #111687 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!

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\n" ); document.write( "1) Jay's test scores were 78,80,95, and 81. He took his last test for the quarter on Friday. What must he get to maintain a B average (between 80 and 89)
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\n" ); document.write( "Since \"B\" average is bet. 80-89, we'll use the 80 average (minimum) for the eqn. Atleast if he gets higher than this is better right?
\n" ); document.write( "\"Test=T%5B1%5D\", We'll do averaging,
\n" ); document.write( "\"%28T%5B1%5D%2BT%5B2%5D%2BT%5B3%5D%2BT%5B5%5D%29%2F5=80\"
\n" ); document.write( "\"%2878%2B80%2B95%2B81%2BT%5B5%5D%29%2F5=80\", adding & cross multiply:
\n" ); document.write( "\"334%2BT%5B5%5D=5%2A80\"
\n" ); document.write( "\"T%5B5%5D=400-334\" ----> \"T%5B5%5D=66\" ---------> FINAL SCORE to get ave at least 80 and maintain \"B\" average.\r
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\n" ); document.write( "\n" ); document.write( "2) Ernie's average after 3 tests is at least 72%. If two of his test scores were 55 & 85, what could he have scored on his 3rd test?\r
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\n" ); document.write( "\n" ); document.write( "Same thing, \"Averaging\"
\n" ); document.write( "\"%28T%5B1%5D%2BT%5B2%5D%2BT%5B3%5D%29%2F3=72\"
\n" ); document.write( "\"%2855%2B85%2BT%5B3%5D%29%2F3=72\", adding & cross multiply,
\n" ); document.write( "\"140%2BT%5B3%5D=3%2A72\"
\n" ); document.write( "\"T%5B3%5D=216-140\" ----> \"T%5B3%5D=76\" ------> FINAL SCORE to get 72 AVERAGE.\r
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\n" ); document.write( "\n" ); document.write( "3) If the square patio has \"X\" dimensions, the new dimensions now are:
\n" ); document.write( "\"Length=x%2B6\" ----------> increased by 6'
\n" ); document.write( "\"Width=2x\" ------------> doubled
\n" ); document.write( "This becomes a rectangle now since it has 2 diff dimensions.
\n" ); document.write( "The \"loophole\" with this you can get different orig. dimensions because the New Perimeter ranges from 30'-45'. Why? Simply we 'll base our computation in solving for \"X\" for the New Perimeter.
\n" ); document.write( "Okay, we'll pick the New Perimeter as \"42ft\", then
\n" ); document.write( "\"P=2%28L%2BW%29\"
\n" ); document.write( "\"42=2%28x%2B6%2B2x%29\"
\n" ); document.write( "\"42=2%283x%2B6%29\" -------------> \"42=6x%2B12\" ---------> \"42-12=6x\"
\n" ); document.write( "\"cross%2830%295%2Fcross%286%29=cross%286%29x%2Fcross%286%29\"
\n" ); document.write( "\"x=5ft\"
\n" ); document.write( "SIZE of the orig square patio is \"5ftx5ft\" based on the NEW PERIMETER of \"42ft\"\r
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\n" ); document.write( "\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo

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