document.write( "Question 151827: find the length and width of a rectangular lot with a perimeter of 88 meters if the length is 4 meters more than the width. \n" ); document.write( "
Algebra.Com's Answer #111630 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! p=2l*2w \n" ); document.write( "88=2(w+4)+2w \n" ); document.write( "88=2w+8+2w \n" ); document.write( "88=4w-8 \n" ); document.write( "4w=88-8 \n" ); document.write( "4w=80 \n" ); document.write( "w=80/4 \n" ); document.write( "w=20 meters for the width. \n" ); document.write( "l=20+4=24 meters for the length. \n" ); document.write( "proof: \n" ); document.write( "2*24+2*20=88 \n" ); document.write( "48+40=88 \n" ); document.write( "88=88 \n" ); document.write( " \n" ); document.write( " |