document.write( "Question 151827: find the length and width of a rectangular lot with a perimeter of 88 meters if the length is 4 meters more than the width. \n" ); document.write( "
Algebra.Com's Answer #111630 by checkley77(12844)\"\" \"About 
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p=2l*2w
\n" ); document.write( "88=2(w+4)+2w
\n" ); document.write( "88=2w+8+2w
\n" ); document.write( "88=4w-8
\n" ); document.write( "4w=88-8
\n" ); document.write( "4w=80
\n" ); document.write( "w=80/4
\n" ); document.write( "w=20 meters for the width.
\n" ); document.write( "l=20+4=24 meters for the length.
\n" ); document.write( "proof:
\n" ); document.write( "2*24+2*20=88
\n" ); document.write( "48+40=88
\n" ); document.write( "88=88
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