document.write( "Question 151844: Consecutive Integers. Find three consecutive integers such that the sum of their squares is 77. \n" ); document.write( "
Algebra.Com's Answer #111618 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! X^2+(X+1)^2+(X+2)^2=77 \n" ); document.write( "X^2+X^2+2X+1+X^2+4X+4=77 \n" ); document.write( "3X^2+6X+5=77 \n" ); document.write( "3X^2+6X+5-77=0 \n" ); document.write( "3X^2+6X-72=0 \n" ); document.write( "3(X^2+2X-24)=0 \n" ); document.write( "3(X+6)(X-4)=0 \n" ); document.write( "X-4=0 \n" ); document.write( "X=4, 5 & 6 ANSWERS. \n" ); document.write( "PROOF: \n" ); document.write( "462+5^2=662=77 \n" ); document.write( "16+25=36=77 \n" ); document.write( "77=77 \n" ); document.write( " |