document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151777>Question 151777</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can someone please help me solve this linear system in three variables?\r<BR>\n" );
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document.write( "x-3y=11<BR>\n" );
document.write( "5y+z=4<BR>\n" );
document.write( "-x+z=2<BR>\n" );
document.write( "{(?,?,?)} </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111611 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> adding 1st and 3rd eqns __ z-3y=13 __ adding 3y __ z=3y+13\r<BR>\n" );
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document.write( "substituting into 2nd eqn __ 5y+(3y+13)=4 __ subtracting 13 __ 8y=-9 __ y=-9/8\r<BR>\n" );
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document.write( "substituting into 1st eqn __ x-3(-9/8)=11 __ subtracting 27/8 __ x=61/8\r<BR>\n" );
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document.write( "substituting into 3rd eqn __ -(61/8)+z=2 __ adding 61/8 __ z=77/8 </SPAN>\n" );
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