document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151790>Question 151790</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi,\r<BR>\n" );
document.write( "\n" );
document.write( "I need help with the following: I did the work just want to make sure its right\r<BR>\n" );
document.write( "\n" );
document.write( ".Explain how to apply elimination in solving a system of equations.<BR>\n" );
document.write( "       <BR>\n" );
document.write( "To solve a system of linear equation by elimination process\r<BR>\n" );
document.write( "\n" );
document.write( "   1)Bring the co-efficient of any one variable to the same .\r<BR>\n" );
document.write( "\n" );
document.write( "   2)  If the signs of both variable are same  (having the same co-efficient) then subtract the two equation's.\r<BR>\n" );
document.write( "\n" );
document.write( "a.	Explain how to apply substitution in solving a system of equations.\r<BR>\n" );
document.write( "\n" );
document.write( "   3)If the signs are different then add the two equation’s so that like terms get eliminated.<BR>\n" );
document.write( "      <BR>\n" );
document.write( "   4)The value of one variable is calculated<BR>\n" );
document.write( "  <BR>\n" );
document.write( "   5)By substituting the value of known variable unknown variable can be found.\r<BR>\n" );
document.write( "\n" );
document.write( "a.	Demonstrate each technique in solving the system<BR>\n" );
document.write( "3x + 9y = 12<BR>\n" );
document.write( "5x - 4y = 3<BR>\n" );
document.write( "    Solution: 1. 3x + 9y = 12 \r<BR>\n" );
document.write( "\n" );
document.write( "               2. 5x - 4y = 3 \r<BR>\n" );
document.write( "\n" );
document.write( "             1)L.C.M  of 3,5 = 15 hence bring the co-efficient of x to 15\r<BR>\n" );
document.write( "\n" );
document.write( "               multiply equations(1) by 5 ,  and equations(2) by 3. The two equations \r<BR>\n" );
document.write( "\n" );
document.write( "               reduces to  15x+45y = 60<BR>\n" );
document.write( "                           15x-12y = 9\r<BR>\n" );
document.write( "\n" );
document.write( "              2) subtract the two  equations  we get  57y = 51 , y = 51/57\r<BR>\n" );
document.write( "\n" );
document.write( "              3) substituting the value of y in equations <BR>\n" );
document.write( "		<BR>\n" );
document.write( "		<BR>\n" );
document.write( "		(1) we get<BR>\n" );
document.write( " <BR>\n" );
document.write( "                    3x+9(51/57) = 12\r<BR>\n" );
document.write( "\n" );
document.write( "                             3x = 12- (459/57) = 684-459/57 = 225/57\r<BR>\n" );
document.write( "\n" );
document.write( "                             x = 225/57*3 = 75/57 \r<BR>\n" );
document.write( "\n" );
document.write( "                   solution is x = 75/57   and y = 51/57\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Thank you for your help.<BR>\n" );
document.write( "S\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111595 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111595\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have the correct answers.\r<BR>\n" );
document.write( "\n" );
document.write( "You can easily check you answers by just plugging the value for x and y into the original two equations and verifying the result is \"true\" (that is 12=12 and 3=3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );