document.write( "Question 151783: Three chemical reactions each produce oxygen. If the first produces twice that of the second, the third produces twice that of the first, and the combined total is 560 cm^3, what volume is produced by each? \n" ); document.write( "

Algebra.Com's Answer #111584 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
Note:
\n" ); document.write( " $\"CR%5B1%5D\"$ = 1st chem. rxn
\n" ); document.write( " $\"CR%5B2%5D\"$ = 2nd chem. rxn
\n" ); document.write( " $\"CR%5B3%5D\"$ = 3rd chem. rxn.
\n" ); document.write( " $\"O%5B2%5D\"$ = Oxygen produced by each rxn.
\n" ); document.write( "1st condition: $\"CR%5B1%5D\"$ produces twice that of $\"CR%5B2%5D\"$
\n" ); document.write( "--------> $\"CR%5B1%5D=2O%5B2%5D\"$
\n" ); document.write( "--------> $\"CR%5B2%5D=+O%5B2%5D\"$
\n" ); document.write( "2nd condition: $\"CR%5B3%5D\"$ produces twice that of $\"CR%5B1%5D\"$
\n" ); document.write( "--------> $\"CR%5B3%5D=2%282O%5B2%5D%29\"$
\n" ); document.write( "NOW, equating the 3 values of the chemical rxn that has combined total of 560cc
\n" ); document.write( " $\"CR%5B1%5D%2BCR%5B2%5D%2BCR%5B3%5D=560cc\"$ --------------------> working eqn
\n" ); document.write( " $\"2O%5B2%5D%2BO%5B2%5D%2B2%282O%5B2%5D%29=560cc\"$
\n" ); document.write( " $\"3O%5B2%5D%2B4O%5B2%5D=560cc\"$
\n" ); document.write( " $\"cross%287%29O%5B2%5D%2Fcross%287%29=cross%28560%2980cc%2Fcross%287%29\"$
\n" ); document.write( " $\"O%5B2%5D=80cc\"$ ----------------> amount of Oxygen produced by $\"CR%5B2%5D\"$
\n" ); document.write( "FOR $\"CR%5B1%5D\"$ = $\"2O%5B2%5D=2%2A80=160cc\"$
\n" ); document.write( "FOR $\"CR%5B3%5D\"$ = $\"2%282O%5B2%5D%29=2%282%2A80%29=2%28160%29=320cc\"$
\n" ); document.write( "In doubt? Go back working eqn,
\n" ); document.write( " $\"160%2B80%2B320=560\"$
\n" ); document.write( " $\"560=560\"$ , note: cc= cubic centimeter= $\"cm%5E3\"$
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

\n" );