document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151786>Question 151786</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One grade of oil has 0.50% of an additive, and a higher grade has 0.75% of the additive.  How many liters of each must be used to have 1000L of a mixture with 0.65% of the additive? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111582 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111582\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .75x+.50(1000-x)=.65*1000<BR>\n" );
document.write( ".75x+500-.50x=650<BR>\n" );
document.write( ".25x=650-500<BR>\n" );
document.write( ".25x=150<BR>\n" );
document.write( "x=150/.25<BR>\n" );
document.write( "x=600 L of 65% additive.<BR>\n" );
document.write( "1000-600=400 L of 50% additive.<BR>\n" );
document.write( "Proof.<BR>\n" );
document.write( ".75*600+.5*400=650<BR>\n" );
document.write( "450+200=650<BR>\n" );
document.write( "650=650 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );