document.write( "Question 151766: two busses are 515 miles apart. At 9:30 AM they start traveling toward each other at rates of 48 and 55 miles per hour. At what time will they pass each other? \n" ); document.write( "
Algebra.Com's Answer #111570 by orca(409)\"\" \"About 
You can put this solution on YOUR website!
Use the following fact to set up an equation:
\n" ); document.write( "when they meet each other, the sum of the distances they traveled is 515 miles .\r
\n" ); document.write( "\n" ); document.write( "Suppose that it takes x hours for them to meet each other.
\n" ); document.write( "The distance covered by the first bus is 48x.
\n" ); document.write( "The distance covered by the first bus is 55x.
\n" ); document.write( "Their sum is 48x + 55x.
\n" ); document.write( "Setting it equal to 515, we have
\n" ); document.write( "48x + 55x = 515\r
\n" ); document.write( "\n" ); document.write( "Solving the equation for x, we obtain
\n" ); document.write( "103x = 515
\n" ); document.write( "x = 5
\n" ); document.write( "Therefore it takes 5 hours for them to meet each other.
\n" ); document.write( "So the time is 14:30.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );