document.write( "Question 151766: two busses are 515 miles apart. At 9:30 AM they start traveling toward each other at rates of 48 and 55 miles per hour. At what time will they pass each other? \n" ); document.write( "
Algebra.Com's Answer #111570 by orca(409)![]() ![]() ![]() You can put this solution on YOUR website! Use the following fact to set up an equation: \n" ); document.write( "when they meet each other, the sum of the distances they traveled is 515 miles .\r \n" ); document.write( "\n" ); document.write( "Suppose that it takes x hours for them to meet each other. \n" ); document.write( "The distance covered by the first bus is 48x. \n" ); document.write( "The distance covered by the first bus is 55x. \n" ); document.write( "Their sum is 48x + 55x. \n" ); document.write( "Setting it equal to 515, we have \n" ); document.write( "48x + 55x = 515\r \n" ); document.write( "\n" ); document.write( "Solving the equation for x, we obtain \n" ); document.write( "103x = 515 \n" ); document.write( "x = 5 \n" ); document.write( "Therefore it takes 5 hours for them to meet each other. \n" ); document.write( "So the time is 14:30.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |