document.write( "Question 151754: Juan left home on his bicycle at 10:00a.m. traveling at 21km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 63km/h, what time did Juan's brother overtake him? \n" ); document.write( "

Algebra.Com's Answer #111562 by nerdybill(7384) $\"\"$ $\"About$

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Juan left home on his bicycle at 10:00a.m. traveling at 21km/h. At noon, his brother set out after him on his motorcycle following the same route. If the motorcycle traveled at 63km/h, what time did Juan's brother overtake him?
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\n" ); document.write( "You will need to apply the \"distance\" formula:
\n" ); document.write( "d = rt
\n" ); document.write( "where
\n" ); document.write( "d is distance
\n" ); document.write( "r is rate or speed
\n" ); document.write( "t is time
\n" ); document.write( ".
\n" ); document.write( "Let x = amount of time Juan's brother took to overtake him
\n" ); document.write( ".
\n" ); document.write( "x+2 = time Juan was on his bicycle
\n" ); document.write( ".
\n" ); document.write( "\"distance traveled by Juan\" = \"distance traveled by Juan's brother\"
\n" ); document.write( ".
\n" ); document.write( "21(x+2) = 63x
\n" ); document.write( "21x + 42 = 63x
\n" ); document.write( "42 = 42x
\n" ); document.write( "1 hour = x
\n" ); document.write( ".
\n" ); document.write( "Therefore, Juan's brother overtook him 1 hour after starting. And, since he started at noon, Juan's brother will overtake him at 1 PM.
\n" ); document.write( ".
\n" ); document.write( "Answer: 1 PM \n" ); document.write( "

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