document.write( "Question 151673: a train leaves station m and travels west at 35 km/hr. One hour later, a faster train leaves station m and also travels west on a parallel track at 40 km/hr. How far from station m will the faster train catch the slower one? \n" ); document.write( "
Algebra.Com's Answer #111556 by ankor@dixie-net.com(22740)\"\" \"About 
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leaves station m and travels west at 35 km/hr. One hour later, a faster train leaves station m and also travels west on a parallel track at 40 km/hr. How far from station m will the faster train catch the slower one?
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\n" ); document.write( "Find the time required for the faster train to catch up, then find the distance
\n" ); document.write( "Let t = time for the faster train
\n" ); document.write( "then
\n" ); document.write( "(t+1) = time for slower train
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\n" ); document.write( "When this happens they will have traveled the same distance
\n" ); document.write( "Write a distance equation: Dist = speed * time
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\n" ); document.write( "Fast train dist = slow train dist
\n" ); document.write( "40t = 35(t+1)
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\n" ); document.write( "40t = 35t + 35
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\n" ); document.write( "40t - 35t = 35
\n" ); document.write( ":
\n" ); document.write( "5t = 35
\n" ); document.write( "t = \"35%2F5\"
\n" ); document.write( "t = 7 hrs
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\n" ); document.write( "Find the dist using the slow train (travel time 8 hrs)
\n" ); document.write( "35 * 8 = 280 mi
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\n" ); document.write( "Check solution using the fast train
\n" ); document.write( "40 * 7 = 280 mi \n" ); document.write( "
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