document.write( "Question 151733: How do you graph these inequalities 2x > -6 and x - 4 < 3?
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Algebra.Com's Answer #111549 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Let's solve the first inequality \"2x%3E-6\":\r
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\n" ); document.write( "\n" ); document.write( "\"2x%3E-6\" Start with the first inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E%28-6%29%2F%282%29\" Divide both sides by \"2\" to isolate \"x\". \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E-3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve the second inequality \"x-4%3C3\":\r
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\n" ); document.write( "\n" ); document.write( "\"x-4%3C3\" Start with the second inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C3%2B4\" Add \"4\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C7\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x%3E-3\" and \"x%3C7\"\r
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\n" ); document.write( "\n" ); document.write( "This combines to the compound inequality \"-3%3Cx%3C7\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "So the answer in set-builder notation is \r
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\n" ); document.write( "\n" ); document.write( "Here's the graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( " Graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( "Note:\r
\n" ); document.write( "\n" ); document.write( "There is an open circle at \"x=-3\" which means that we're excluding this value from the solution set\r
\n" ); document.write( "\n" ); document.write( "Also, there is an open circle at \"x=7\" which means that we're excluding this value from the solution set.\r
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