document.write( "Question 151736: How do you graph x + 5 > 2x + 1 and -4x < -8?
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Algebra.Com's Answer #111543 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Let's solve the first inequality \"x%2B5%3E2x%2B1\":\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B5%3E2x%2B1\" Start with the first inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E2x%2B1-5\" Subtract \"5\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x-2x%3E1-5\" Subtract \"2x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-x%3E1-5\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"-x%3E-4\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3C%28-4%29%2F%28-1%29\" Divide both sides by \"-1\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"x%3C4\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "Now let's solve the second inequality \"-4x%3C-8\":\r
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\n" ); document.write( "\n" ); document.write( "\"-4x%3C-8\" Start with the second inequality.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E%28-8%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate \"x\". note: Remember, the inequality sign flips when we divide both sides by a negative number. \r
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\n" ); document.write( "\n" ); document.write( "\"x%3E2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x%3C4\" and \"x%3E2\"\r
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\n" ); document.write( "\n" ); document.write( "This answer combines to the compound inequality \"2%3Cx%3C4\"\r
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\n" ); document.write( "\n" ); document.write( "So the answer in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "So the answer in set-builder notation is \r
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\n" ); document.write( "\n" ); document.write( "Here's the graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( " Graph of the solution set\r
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\n" ); document.write( "\n" ); document.write( "Note:\r
\n" ); document.write( "\n" ); document.write( "There is an open circle at \"x=2\" which means that we're excluding this value from the solution set\r
\n" ); document.write( "\n" ); document.write( "Also, there is an open circle at \"x=4\" which means that we're excluding this value from the solution set.
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