document.write( "Question 151702: Solve 45x^2-60x+20=0 \n" ); document.write( "
Algebra.Com's Answer #111518 by jim_thompson5910(35256)\"\" \"About 
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\"45x%5E2-60x%2B20\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"5%289x%5E2-12x%2B4%29\" Factor out the GCF \"5\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's focus on the inner expression \"9x%5E2-12x%2B4\"\r
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"9x%5E2-12x%2B4\", we can see that the first coefficient is \"9\", the second coefficient is \"-12\", and the last term is \"4\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"9\" by the last term \"4\" to get \"%289%29%284%29=36\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"36\" (the previous product) and add to the second coefficient \"-12\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"36\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"36\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,9,12,18,36\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-9,-12,-18,-36\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"36\".\r
\n" ); document.write( "\n" ); document.write( "1*36
\n" ); document.write( "2*18
\n" ); document.write( "3*12
\n" ); document.write( "4*9
\n" ); document.write( "6*6
\n" ); document.write( "(-1)*(-36)
\n" ); document.write( "(-2)*(-18)
\n" ); document.write( "(-3)*(-12)
\n" ); document.write( "(-4)*(-9)
\n" ); document.write( "(-6)*(-6)\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-12\":\r
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First NumberSecond NumberSum
1361+36=37
2182+18=20
3123+12=15
494+9=13
666+6=12
-1-36-1+(-36)=-37
-2-18-2+(-18)=-20
-3-12-3+(-12)=-15
-4-9-4+(-9)=-13
-6-6-6+(-6)=-12
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"-6\" and \"-6\" add to \"-12\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"-6\" and \"-6\" both multiply to \"36\" and add to \"-12\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-12x\" with \"-6x-6x\". Remember, \"-6\" and \"-6\" add to \"-12\". So this shows us that \"-6x-6x=-12x\".\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2Bhighlight%28-6x-6x%29%2B4\" Replace the second term \"-12x\" with \"-6x-6x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%289x%5E2-6x%29%2B%28-6x%2B4%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%283x-2%29%2B%28-6x%2B4%29\" Factor out the GCF \"3x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"3x%283x-2%29-2%283x-2%29\" Factor out \"2\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-2%29%283x-2%29\" Combine like terms. Or factor out the common term \"3x-2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-2%29%5E2\" Condense the common factors.\r
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\n" ); document.write( "\n" ); document.write( "So the expression goes from \"5%289x%5E2-12x%2B4%29\" and factors further to \"5%283x-2%29%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "So \"45x%5E2-60x%2B20\" factors to \"5%283x-2%29%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"5%283x-2%29%5E2=0\" Set the factored expression equal to zero\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-2%29%5E2=0\" Divide both sides by 5.\r
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\n" ); document.write( "\n" ); document.write( "\"3x-2=0\" Take the square root of both sides\r
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\n" ); document.write( "\n" ); document.write( "\"3x=0%2B2\" Add \"2\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"3x=2\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%282%29%2F%283%29\" Divide both sides by \"3\" to isolate \"x\".\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x=2%2F3\" \r
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\n" ); document.write( "\n" ); document.write( "Which approximates to \"x=0.667\" \r
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