document.write( "Question 151631: Ramona is staying at a vacation resort called Stony Cabins. She rents a canoe and take 1.5 hours to paddle her canoe upstream. Ramona turns her canoe around and returns downstream to her cabin in exactly 1 hour. What is the rate of the creek's current and the rate of Ramona's paddling in still water? \n" ); document.write( "
Algebra.Com's Answer #111509 by ankor@dixie-net.com(22740)\"\" \"About 
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Ramona is staying at a vacation resort called Stony Cabins. She rents a canoe and take 1.5 hours to paddle her canoe upstream. Ramona turns her canoe around and returns downstream to her cabin in exactly 1 hour. What is the rate of the creek's current and the rate of Ramona's paddling in still water?
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\n" ); document.write( "We need to know the distance (d) to solve this problem, however we can find the\
\n" ); document.write( "relationship between her speed and the current;
\n" ); document.write( ":
\n" ); document.write( "Let x = paddling speed
\n" ); document.write( "Let y = current speed
\n" ); document.write( "then
\n" ); document.write( "Speed up stream = (x-y)
\n" ); document.write( "Speed downstream = (x+y)
\n" ); document.write( ":
\n" ); document.write( "Write 2 distance equations: Dist = time * speed
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\n" ); document.write( "1.5(x-y) = d
\n" ); document.write( "1(x+y) = d
\n" ); document.write( ":
\n" ); document.write( "Therefore we can write it:
\n" ); document.write( "1.5(x-y) = 1(x+y)
\n" ); document.write( "1.5x - 1.5y = x + y
\n" ); document.write( "1.5x - x = y + 1.5y
\n" ); document.write( ".5x = 2.5y
\n" ); document.write( "or
\n" ); document.write( "x = 5y We know the paddling speed is 5 times the current speed \n" ); document.write( "
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