document.write( "Question 151689: A car rental compan has two rental rates. rate 1 is $72 per day plus $0.16 per mile. Rate 2 is $144 per day plus $0.08 per mile. If you plan to rent for one week, how many miles would you need to drive to pay less by taking rate 2? \n" ); document.write( "
Algebra.Com's Answer #111502 by Earlsdon(6294)\"\" \"About 
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First, we'll express the two rates as equations:
\n" ); document.write( "\"R%5B1%5D+=+72%2Fd+%2B+0.16%2Fm\" Rate 1 is $72 per day + $0.16 per mile.
\n" ); document.write( "\"R%5B2%5D+=+144%2Fd+%2B+0.08%2Fm\" Rate 2 is $144 per day + $0.08 per mile.
\n" ); document.write( "Since you are renting for one week (7 days) and letting x = the number of miles, we can refine the equations a bit:
\n" ); document.write( "\"R%5B1%5D+=+72%287%29%2B0.16x\"=\"504%2B0.16x\"
\n" ); document.write( "\"R%5B2%5D+=+144%287%29%2B0.08x\"=\"1008%2B0.08x\"
\n" ); document.write( "Now the question is, what value of x (number of miles) will make \"R%5B2%5D%3CR%5B1%5D\", so we need to write the inequality:
\n" ); document.write( "\"1008%2B0.08x+%3C+504%2B0.16x\" Now we solve this inequality for x. Subtract 0.08x from both sides.
\n" ); document.write( "\"1008+%3C+504%2B0.08x\" Now subtract 504 from both sides.
\n" ); document.write( "\"504+%3C+0.08x\" Finally, divide both sides by 0.08
\n" ); document.write( "\"6300+%3C+x\" or \"x+%3E+6300\"
\n" ); document.write( "So, you would need to drive more than 6300 miles to pay less with rate 2.
\n" ); document.write( "Let's check the answer by driving 6301 miles (6301 > 6300):
\n" ); document.write( "\"R%5B1%5D+=+504%2B0.16%286301%29\"
\n" ); document.write( "\"R%5B1%5D+=+504%2B1008.16\"
\n" ); document.write( "\"R%5B1%5D+=+1512.16\"
\n" ); document.write( "Rate 1 would be $1512.16 for one week's rental driven 6301 miles.
\n" ); document.write( "\"R%5B2%5D+=+1008%2B0.08%286301%29\"
\n" ); document.write( "\"R%5B2%5D+=+1008%2B504.08\"
\n" ); document.write( "\"R%5B2%5D+=+1512.08\"
\n" ); document.write( "Rate 2 would be $1512.08 for one week's rental driven 6301 miles.
\n" ); document.write( "So you can see that if you were to drive more than 6300 miles for the week, rate 2 would cost you less than rate 1.
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