document.write( "Question 151668: could someone please help me solve this equations using Cramer's rule for three variables? I am just not getting past the point of transforming them into the three different matices.\r
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Algebra.Com's Answer #111492 by Edwin McCravy(20065)\"\" \"About 
You can put this solution on YOUR website!
could someone please help me solve this equations using Cramer's rule for three variables? I am just not getting past the point of transforming them into the three different matices.
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document.write( "x-2y=17\r\n" );
document.write( "2y+z=10\r\n" );
document.write( "-x+z=-2\r\n" );
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document.write( "Put in +0 times every missing letter:\r\n" );
document.write( "Put in understood 1 coefficients:\r\n" );
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document.write( " 1x - 2y + 0z = 17\r\n" );
document.write( " 0x + 2y + 1z = 10\r\n" );
document.write( "-1x + 0y + 1z = -2\r\n" );
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document.write( "You must memorize this:\r\n" );
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document.write( "This system:\r\n" );
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document.write( "\"Ax+%2B+By+%2B+Cz+=+D\"\r\n" );
document.write( "\"Ex+%2B+Fy+%2B+Gz+=+H\"\r\n" );
document.write( "\"Ix+%2B+Jy+%2B+Kz+=+L\"\r\n" );
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document.write( "has this solution:\r\n" );
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document.write( "              \r\n" );
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document.write( "The 3 denominators are all the same. They are the\r\n" );
document.write( "coefficients of the unknowns in the same configuration\r\n" );
document.write( "as they are in the original equations.\r\n" );
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document.write( "The column of constants is the column of numbers right of\r\n" );
document.write( "the equal signs, namely this: \"matrix%283%2C1%2CD%2CH%2CL%29\".\r\n" );
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document.write( "The numerator for the FIRST unknown, x, is like its denominator\r\n" );
document.write( "except that the FIRST column \"matrix%283%2C1%2CA%2CE%2CI%29\".is replaced by   \"matrix%283%2C1%2CD%2CH%2CL%29\".\r\n" );
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document.write( "The numerator for the SECOND unknown, y, is like its denominator\r\n" );
document.write( "except that the SECOND column \"matrix%283%2C1%2CB%2CF%2CJ%29\".is replaced by   \"matrix%283%2C1%2CD%2CH%2CL%29\".\r\n" );
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document.write( "The numerator for the THIRD unknown, x, is like its denominator\r\n" );
document.write( "except that the THIRD column \"matrix%283%2C1%2CC%2CG%2CK%29\".is replaced by   \"matrix%283%2C1%2CD%2CH%2CL%29\".\r\n" );
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document.write( "-----\r\n" );
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document.write( "This system:\r\n" );
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document.write( "  \"1x+-+2y+%2B+0z+=+17\"\r\n" );
document.write( "  \"0x+%2B+2y+%2B+1z+=+10\"\r\n" );
document.write( " \"-1x+%2B+0y+%2B+1z+=+-2\"\r\n" );
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document.write( "has this solution:\r\n" );
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document.write( "              \r\n" );
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document.write( "The 3 denominators are all the same. They are the\r\n" );
document.write( "coefficients of the unknowns in the same configuration\r\n" );
document.write( "as they are in the original equations.\r\n" );
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document.write( "The column of constants is the column of numbers right of\r\n" );
document.write( "the equal signs, namely this: \"matrix%283%2C1%2C17%2C10%2C-2%29\".\r\n" );
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document.write( "The numerator for the FIRST unknown, x, is like its denominator\r\n" );
document.write( "except that the FIRST column \"matrix%283%2C1%2C1%2C0%2C-1%29\".is replaced by   \"matrix%283%2C1%2C17%2C10%2C-2%29\".\r\n" );
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document.write( "The numerator for the SECOND unknown, y, is like its denominator\r\n" );
document.write( "except that the SECOND column \"matrix%283%2C1%2C-2%2C2%2C0%29\".is replaced by   \"matrix%283%2C1%2C17%2C10%2C-2%29\".\r\n" );
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document.write( "The numerator for the THIRD unknown, z, is like its denominator\r\n" );
document.write( "except that the THIRD column \"matrix%283%2C1%2C0%2C1%2C1%29\".is replaced by   \"matrix%283%2C1%2C17%2C10%2C-2%29\".\r\n" );
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document.write( "Do you know how to evaluate the determinants? If not\r\n" );
document.write( "post again asking how:\r\n" );
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document.write( "\"x=58%2F4=29%2F2\"       \"y=%28-5%29%2F4\"       \"z=50%2F4=25%2F2\"\r\n" );
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document.write( "Edwin
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