document.write( "Question 22792: Good Evening, I am working on solving this problem. Please help. I'm still confused on the process. \r
\n" ); document.write( "\n" ); document.write( "4^x+1=64 Where appropriate, include approximations to the nearest thousandth.
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Algebra.Com's Answer #11146 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
I assume that the use of logarithms is expected.\r
\n" ); document.write( "\n" ); document.write( "\"4%5Ex+%2B+1+=+64\" Subtract 1 from both sides of the equation.
\n" ); document.write( "\"4%5Ex+=+63\" Take the log of both sides.
\n" ); document.write( "\"xlog4+=+log63\" Divide both sides by \"log4\"
\n" ); document.write( "\"x+=+%28log63%29%2Flog4\" You can do this on your calculator or use a table of logarithms.
\n" ); document.write( "\"x+=+2.989\" to the nearest thousandth.\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"4%5E%282.989%29+%2B+1+=+63.031+%2B+1\" = 64.031
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