document.write( "Question 151613: Find an equation of the line satisfying the given conditions.
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Algebra.Com's Answer #111444 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If you want to find the equation of line with a given a slope of \"3%2F2\" which goes through the point (0,2), you can simply use the point-slope formula to find the equation:\r
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\n" ); document.write( "\n" ); document.write( "---Point-Slope Formula---
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is the given point\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=%283%2F2%29%28x-0%29\" Plug in \"m=3%2F2\", \"x%5B1%5D=0\", and \"y%5B1%5D=2\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=%283%2F2%29x%2B%283%2F2%29%28-0%29\" Distribute \"3%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-2=%283%2F2%29x%2B0\" Multiply \"3%2F2\" and \"-0\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2F2%29x%2B0%2B2\" Add 2 to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2F2%29x%2B2\" Combine like terms \"0\" and \"2\" to get \"2\" \r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line with a slope of \"3%2F2\" which goes through the point (0,2) is:\r
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\n" ); document.write( "\n" ); document.write( "\"y=%283%2F2%29x%2B2\" which is now in \"y=mx%2Bb\" form where the slope is \"m=3%2F2\" and the y-intercept is \"b=2\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%283%2F2%29x%2B2\" and plot the point (0,2), we get (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%283%2F2%29x%2B2\" through the point (0,2)\r
\n" ); document.write( "\n" ); document.write( "and we can see that the point lies on the line. Since we know the equation has a slope of \"3%2F2\" and goes through the point (0,2), this verifies our answer.
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