document.write( "Question 151591: The measure of the supplement of an angle is 10 percent more than four times the measure of the angle. Find the measures of both angles. \n" ); document.write( "
Algebra.Com's Answer #111424 by jojo14344(1513)\"\" \"About 
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We all know supplementary angles are \"2\" angles that add to 180 degrees.
\n" ); document.write( "For that reason, we can make an equation \"A%2BB=180\" ---------> eqn 1
\n" ); document.write( "It shows angle B is a supplemantary of angle A, and to satisfy the other condition 1 being \"10percent\" more than \"4times\" it's measure angle.
\n" ); document.write( "Putting that into eqn, \"A=4B%2A1.10\", right? ------> eqn 2
\n" ); document.write( "We multiply by \"1.10\" because it's \"10percent\" more.
\n" ); document.write( ".
\n" ); document.write( "Substitute eqn 2 in eqn 1 we have
\n" ); document.write( "\"%284B%29%281.10%29%2BB=180\"
\n" ); document.write( "\"4.40B%2BB=180\"
\n" ); document.write( "\"5.40B=180\" ---------> \"cross%285.40%29B%2Fcross%285.40%29=cross%28180%2933.33333%2Fcross%285.40%29\"
\n" ); document.write( "\"B=33.333333deg\"
\n" ); document.write( "The other angle as per eqn 1: \"A%2B33.333333=180\" ----> \"A=146.666667deg\"
\n" ); document.write( "To check:
\n" ); document.write( "As it stated the supplement angle \"10percent\" more than \"4times\" it's measurement,go back eqn 2,
\n" ); document.write( "\"146.666667=4%2833.33333%29%2A1.10\"
\n" ); document.write( "\"146.6666667=146.6666667\"
\n" ); document.write( "Also, in eqn 1
\n" ); document.write( "\"A%2BB=180\" ------------> \"146.666667%2B33.33333=180\"
\n" ); document.write( "\"180=180\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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