document.write( "Question 151563: Find three consecutive even integers such that five times the second equals twice the sum of the first and the third? \n" ); document.write( "
Algebra.Com's Answer #111422 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! LET X, X+2 & X+4 BE THE THREE EVEN INTEGERS. \n" ); document.write( "5(X+2)=2(X+X+4) \n" ); document.write( "5X+10=2(2X+4) \n" ); document.write( "5X+10=4X+8 \n" ); document.write( "5X-4X=8-10 \n" ); document.write( "X=-2 IS THE FIRST INTEGER. \n" ); document.write( "-2=2=0 IS THE SECOND INTEGER. \n" ); document.write( "-2+4=2 IS THE THIRD INTEGER. \n" ); document.write( "PROOF: \n" ); document.write( "5*0=2(-2+2) \n" ); document.write( "0=2*0 \n" ); document.write( "0=0 \n" ); document.write( " |