document.write( "Question 151543: I have answered solved the equation and I believe it is right but I don't know how to check it.
\n" ); document.write( "9x^2+24x+15=0
\n" ); document.write( "(3x+5)(3x+3)
\n" ); document.write( "(3x+5)=0
\n" ); document.write( " 3x=-5
\n" ); document.write( " x= -5/3
\n" ); document.write( " or
\n" ); document.write( "(3x+3)=0
\n" ); document.write( " 3x=-3
\n" ); document.write( " x=-1
\n" ); document.write( "Now when I try to put it in the original equation to check it... my problem is
\n" ); document.write( "9(-5/3)^2+24(-5/3)+15 I don't know how to do the fractions with exponents so can you show me how to do the equation to check it? Thanks Dianne
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Algebra.Com's Answer #111402 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2B24x%2B15=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=9\", \"b=24\", and \"c=15\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%2824%29+%2B-+sqrt%28+%2824%29%5E2-4%289%29%2815%29+%29%29%2F%282%289%29%29\" Plug in \"a=9\", \"b=24\", and \"c=15\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24+%2B-+sqrt%28+576-4%289%29%2815%29+%29%29%2F%282%289%29%29\" Square \"24\" to get \"576\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24+%2B-+sqrt%28+576-540+%29%29%2F%282%289%29%29\" Multiply \"4%289%29%2815%29\" to get \"540\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24+%2B-+sqrt%28+36+%29%29%2F%282%289%29%29\" Subtract \"540\" from \"576\" to get \"36\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24+%2B-+sqrt%28+36+%29%29%2F%2818%29\" Multiply \"2\" and \"9\" to get \"18\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24+%2B-+6%29%2F%2818%29\" Take the square root of \"36\" to get \"6\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-24+%2B+6%29%2F%2818%29\" or \"x+=+%28-24+-+6%29%2F%2818%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-18%29%2F%2818%29\" or \"x+=++%28-30%29%2F%2818%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+-1\" or \"x+=+-5%2F3\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So our answers are \"x+=+-1\" or \"x+=+-5%2F3\" \r
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\n" ); document.write( "\n" ); document.write( "Check:\r
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\n" ); document.write( "\n" ); document.write( "Let's check the solution \"x+=+-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2B24x%2B15=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"9%28-1%29%5E2%2B24%28-1%29%2B15=0\" Plug in \"x+=+-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"9%281%29%2B24%28-1%29%2B15=0\" Square -1 to get 1\r
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\n" ); document.write( "\n" ); document.write( "\"9-24%2B15=0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" Combine like terms. Since the equation is true, this means that \"x+=+-1\" is a solution.\r
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\n" ); document.write( "\n" ); document.write( "Let's check the solution \"x+=+-5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2%2B24x%2B15=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"9%28-5%2F3%29%5E2%2B24%28-5%2F3%29%2B15=0\" Plug in \"x+=+-5%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"9%2825%2F9%29%2B24%28-5%2F3%29%2B15=0\" Square \"-5%2F3\" to get \"25%2F9\"\r
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\n" ); document.write( "\n" ); document.write( "\"25%2B24%28-5%2F3%29%2B15=0\" Multiply \"9\" and \"25%2F9\" to get \"9%2825%2F9%29=cross%289%29%2825%2Fcross%289%29%29=25\". So in this case, the denominator is eliminated.\r
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\n" ); document.write( "\n" ); document.write( "\"25-40%2B15=0\" Multiply \"24\" and \"-5%2F3\" to get \"24%28-5%2F3%29=8%2A3%28-5%2F3%29=8%2Across%283%29%28-5%2Fcross%283%29%29=8%28-5%29=-40\". So in this case, the denominator is eliminated.\r
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\n" ); document.write( "\n" ); document.write( "\"0=0\" Combine like terms. Since the equation is true, this means that \"x+=+-5%2F3\" is a solution.
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