document.write( "Question 22774: I am a parent trying to help my son figure out how to solve the following:\r
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document.write( "Bill is twice as old as his brother Dan. In 7 years Bill will be only one and one half as old as Dan. How old is Bill now? \r
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document.write( "I would like the details on solving so I can teach him properly.\r
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document.write( "Thank you.\r
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Algebra.Com's Answer #11140 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! First define the things you are asked for:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let Bill be x years NOW \n" ); document.write( "Let Dan be y years NOW.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, we know x = 2y --eqn1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Also, in 7 years time, Bill will be x+7 and Dan will be y+7. At this point, (x+7) = (3/2)(y+7) --eqn2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "eqn2 simplifies to 2x+14 = 3y+21 \n" ); document.write( "--> 2x - 3y = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, from eqn1, x = 2y, so sub this into the above version of eqn2, which becomes: 2(2y) - 3y = 7, which becomes\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4y - 3y = 7 \n" ); document.write( "y = 7\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence x=2(7) --> x=14\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, Bill is 14 years old now.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "check: \n" ); document.write( "in 7 years, we have ages 14 and 21, where 21 is \"one and one-half\" as much as 14.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this is clear.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |