document.write( "Question 2598: solve the questions give below by factorization
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document.write( " (1)3x2+x=1 (2)4x2+9=12x (3)5x(x+2)=4(3x=1) (4)2x+7=x2 (5)x2-3x=3x=7 (6)3(4x-1)=x2 \n" );
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Algebra.Com's Answer #1114 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! by pure factorisation? \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "1) cannot be factorised easily. You would have to do the \"complete the square\" method.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) \n" ); document.write( "(2x - 3)(2x - 3) = 0 \n" ); document.write( "so 2x-3 = 0 \n" ); document.write( "2x = 3 \n" ); document.write( "x = 3/2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3) 5x(x+2) = 4(3x+1) --> + or - on the last term, seeing as you have \"=\"?\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this does not factorise easily. Again, do you want the \"complete the square\" method?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Same as 3).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "5) \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6) \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Again this does not factorise easily.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |