document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151487>Question 151487</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Word problem help. There is a closet door whose height is 4ft more than its width. To keep the closet closed a cable is attached diagonally from one corner to the other. If the cable measures sqrt194/2 ft, what are the dimensions of the door? \r<BR>\n" );
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document.write( "I thought the height would be: h=4+w and width would be w. But from there I am lost. How would I set this equation up?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111397 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111397\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> good so far...\r<BR>\n" );
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document.write( "the height and width are two legs of a right triangle with the diagonal cable as the hypotenuse\r<BR>\n" );
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document.write( "by Pythagoras __ h^2+w^2=(sqrt(194)/2)^2 __ substituting __ (w+4)^2+w^2=194/4 __ 2w^2+8w+16=194/4\r<BR>\n" );
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document.write( "multiplying by 4 __ 8w^2+32w+64=194 __ subtracting 194 __ 8w^2+32w-130=0 __ dividing by 2 __ 4w^2+16w-65=0\r<BR>\n" );
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document.write( "factoring __ (2w+13)(2w-5)=0\r<BR>\n" );
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document.write( "2w+13=0 __ w=-13/2 __ negative value not realistic\r<BR>\n" );
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document.write( "2w-5=0 __ w=5/2 __ substituting h=(5/2)+4 __ h=6.5 </SPAN>\n" );
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