document.write( "Question 151516: Please help!!
\n" ); document.write( "The growth in the population of a certain rodent at a dump site fits the exponential function, A(t)=336e^(0.031t), where t is the number of years since 1963. Estimate the population in the year 2000.
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Algebra.Com's Answer #111382 by jim_thompson5910(35256)\"\" \"About 
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First, subtract 1963 from 2000 to get \"2000-1963=37\". So in the year 2000, 37 years have elapsed since 1963. This means that in the year 2000, t=37.\r
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\n" ); document.write( "\n" ); document.write( "\"A%28t%29=336e%5E%280.031t%29\" Start with the given function.\r
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\n" ); document.write( "\n" ); document.write( "\"A%2837%29=336e%5E%280.031%2837%29%29\" Plug in \"t=37\"\r
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\n" ); document.write( "\n" ); document.write( "\"A%2837%29=336e%5E%281.147%29\" Multiply 0.031 and 37 to get 1.147\r
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\n" ); document.write( "\n" ); document.write( "\"A%2837%29=336%283.14873%29\" Raise \"e\" to the 1.147th power to get 3.14873\r
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\n" ); document.write( "\n" ); document.write( "\"A%2837%29=1057.97328\" Multiply 336 and 3.14873 to get 1,057.97328\r
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\n" ); document.write( "\n" ); document.write( "So in the year 2000, there will be approximately 1,058 rats. Note: I rounded to the nearest integer.
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