document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22763>Question 22763</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two positive numbers are in a ratio of 9 to 10. If the lesser number is decreased by 6 and the greater number is decreased by 25, the resulting ratio is 2 to 1. Find the greatest of the original numbers.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #11138 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=11138\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let larger number be x\r<BR>\n" );
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document.write( "We have the 2 numbers in ratio 9:10, so smaller number must be 9x/10\r<BR>\n" );
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document.write( "Now change numbers:\r<BR>\n" );
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document.write( "lefthand number reduces to (9x/10) - 6<BR>\n" );
document.write( "righthand number reduces to x - 25\r<BR>\n" );
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document.write( "And now the LH number is twice the size of RH number, ie:\r<BR>\n" );
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document.write( "(9x/10) - 6 = 2(x-25) So solve this...<BR>\n" );
document.write( "(9x/10) - 6 = 2x-50<BR>\n" );
document.write( "(9x/10) = 2x-44<BR>\n" );
document.write( "9x = 20x-440<BR>\n" );
document.write( "11x = 440<BR>\n" );
document.write( "--> x = 40\r<BR>\n" );
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document.write( "9/10ths of this is 36\r<BR>\n" );
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document.write( "so the 2 numbers are 36 and 40.\r<BR>\n" );
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document.write( "do the check too:\r<BR>\n" );
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document.write( "36-6 is 30<BR>\n" );
document.write( "40-25 is 15, half of 30.\r<BR>\n" );
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document.write( "jon.<BR>\n" );
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