document.write( "Question 22747: I need help figuring out which way to proceed to solve this problem.
\n" ); document.write( "log2(x-2) +5 = 8- log2 4. The 2 is the base of the log. I think I should rewrite as log2(x-2) + log2 4 = 3 What is the correct way. I think answer is
\n" ); document.write( " 4(x-2) =2^3 x=4
\n" ); document.write( "Thanks
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Algebra.Com's Answer #11136 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Your first step is flawless!
\n" ); document.write( "\"log%282%2C%28x-2%29%29%2Blog%282%2C4%29=+3\" Now apply the Product Rule for logarithms: \"log%28b%2CM%29%2Blog%28b%2CN%29+=+log%28b%2C%28MN%29%29\"
\n" ); document.write( "\"log%282%2C%28x-2%29%29%2Blog%282%2C4%29+=+log%282%2C%284%28x-2%29%29%29\" = 3 Simplify.
\n" ); document.write( "\"log%282%2C%284x-8%29%29+=+3\" Rewrite this in exponential form: \"log%28b%2Cx%29+=+y\" means \"b%5Ey+=+x\"
\n" ); document.write( "\"2%5E3+=+4x-8\" Simplify and solve for x.
\n" ); document.write( "\"8+=+4x-8\" Add 8 to both sides.
\n" ); document.write( "\"16+=+4x\" Divide both sides by 4.
\n" ); document.write( "\"x+=+4\"\r
\n" ); document.write( "\n" ); document.write( "Check: You could use your calculator but most likely it doesn't have logs to base 2. So, you can change the base of logs from 2 to base 10, which your calculator most-likely can handle.\r
\n" ); document.write( "\n" ); document.write( "Change of base from 2 to 10: \"log%282%2CM%29+=+%28log%2810%2CM%29%29%2Flog%2810%2C2%29\" Apply this to your problem:\r
\n" ); document.write( "\n" ); document.write( "\"log%282%2C%284x-8%29%29+=+%28log%2810%2C%284x-8%29%29%29%2Flog%2810%2C2%29\" Substitute x = 4.
\n" ); document.write( "\"%28log%2810%2C8%29%29%2Flog%2810%2C2%29+=+3\" Use your calculator.
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