document.write( "Question 151438: Could you please help me solve this equation for A, B, and C.\r
\n" ); document.write( "\n" ); document.write( "11x^2-x+8/(x+1)(X^2+4)=A/(x+1)+Bx+C/X^2+4
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Algebra.Com's Answer #111342 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( " Multiply every term by the LCD \"%28x%2B1%29%28x%5E2%2B4%29\" to clear the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"11x%5E2-x%2B8=%28x%5E2%2B4%29%28A%29%2B%28x%2B1%29%28Bx%2BC%29\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"11x%5E2-x%2B8=A%28x%5E2%2B4%29%2B%28x%2B1%29%28Bx%2BC%29\" Rearrange the terms\r
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\n" ); document.write( "\n" ); document.write( "\"11x%5E2-x%2B8=A%28x%5E2%2B4%29%2BBx%5E2%2BCx%2BBx%2BC\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"11x%5E2-x%2B8=Ax%5E2%2B4A%2BBx%5E2%2BCx%2BBx%2BC\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "Notice how the \"x%5E2\" terms on the right side are \"Ax%5E2\" and \"Bx%5E2\". So this means that \"Ax%5E2%2BBx%5E2=11x%5E2\" and \"A%2BB=11\"\r
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\n" ); document.write( "\n" ); document.write( "Also, notice how the \"x\" terms on the right side are \"Bx\" and \"Cx\". So this means that \"Bx%2BCx=-x\" and \"B%2BC=-1\"\r
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\n" ); document.write( "\n" ); document.write( "Finally, the constant terms on the right side are \"4A\" and \"C\". So this means that \"4A%2BC=8\" \r
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\n" ); document.write( "\n" ); document.write( "\"A%2BB=11\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"B=11-A\" Subtract A from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"B%2BC=-1\" Move onto the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"11-A%2BC=-1\" Plug in \"B=11-A\"\r
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\n" ); document.write( "\n" ); document.write( "\"-A%2BC=-12\" Subtract 11 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4A%2B4C=-48\" Multiply both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "Add this equation to equation #3\r
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\n" ); document.write( "\n" ); document.write( "\"-4A%2B4C=-48\"
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\n" ); document.write( "\"0A%2B5C=-40\"\r
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\n" ); document.write( "\n" ); document.write( "\"5C=-40\" Simplify\r
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\n" ); document.write( "\n" ); document.write( "\"C=-8\" Divide both sides by 5.\r
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\n" ); document.write( "\n" ); document.write( "\"4A%2BC=8\" Go back to the third equation\r
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\n" ); document.write( "\n" ); document.write( "\"4A-8=8\" Plug in \"C=-8\"\r
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\n" ); document.write( "\n" ); document.write( "\"4A=16\" Add 8 to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"A=4\" Divide both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "\"B=11-A\" Move onto the first isolated equation\r
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\n" ); document.write( "\n" ); document.write( "\"B=11-4\" Plug in \"A=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"B=7\" Subtract\r
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\n" ); document.write( "\n" ); document.write( "So the value of the constants are \r
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\n" ); document.write( "\n" ); document.write( "\"A=4\", \"B=7\", and \"C=-8\"\r
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\n" ); document.write( "\n" ); document.write( "So this means that the equation is
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