document.write( "Question 151472: I am trying to find b^2-4ac and the number of real solutions for the equation 16-24x+9x^2=0. \r
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\n" ); document.write( "\n" ); document.write( "If I put it in standard form ax^2 + ax + a = 0
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\n" ); document.write( "\n" ); document.write( "b^2-4ac= 24^2 - 4(-9)(-16)=576-576= 0\r
\n" ); document.write( "\n" ); document.write( "So: when the discriminat equals 0 there should be only one solution correct? But how do I find that 1 solution?
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Algebra.Com's Answer #111341 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"16-24x%2B9x%5E2=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2-24x%2B16=0\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "From \"9x%5E2-24x%2B16\" we can see that \"a=9\", \"b=-24\", and \"c=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=b%5E2-4ac\" Start with the discriminant formula.\r
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\n" ); document.write( "\n" ); document.write( "\"D=%28-24%29%5E2-4%289%29%2816%29\" Plug in \"a=9\", \"b=-24\", and \"c=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=576-4%289%29%2816%29\" Square \"-24\" to get \"576\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=576-576\" Multiply \"4%289%29%2816%29\" to get \"%2836%29%2816%29=576\"\r
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\n" ); document.write( "\n" ); document.write( "\"D=0\" Subtract \"576\" from \"576\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "Since the discriminant is equal to zero, this means that there is one real solution.\r
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\n" ); document.write( "\n" ); document.write( "So you are correct. However, I'm not sure where you got a=-9 b=24 c=-16 from.\r
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\n" ); document.write( "\n" ); document.write( "To find the one solution, you have 2 options\r
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\n" ); document.write( "\n" ); document.write( "Option # 1 Quadratic Formula (preferred method)\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2-24x%2B16=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Notice we have a quadratic equation in the form of \"ax%5E2%2Bbx%2Bc\" where \"a=9\", \"b=-24\", and \"c=16\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29\" Start with the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-24%29+%2B-+sqrt%28+%28-24%29%5E2-4%289%29%2816%29+%29%29%2F%282%289%29%29\" Plug in \"a=9\", \"b=-24\", and \"c=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B-+sqrt%28+%28-24%29%5E2-4%289%29%2816%29+%29%29%2F%282%289%29%29\" Negate \"-24\" to get \"24\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B-+sqrt%28+576-4%289%29%2816%29+%29%29%2F%282%289%29%29\" Square \"-24\" to get \"576\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B-+sqrt%28+576-576+%29%29%2F%282%289%29%29\" Multiply \"4%289%29%2816%29\" to get \"576\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B-+sqrt%28+0+%29%29%2F%282%289%29%29\" Subtract \"576\" from \"576\" to get \"0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B-+sqrt%28+0+%29%29%2F%2818%29\" Multiply \"2\" and \"9\" to get \"18\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B-+0%29%2F%2818%29\" Take the square root of \"0\" to get \"0\". \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824+%2B+0%29%2F%2818%29\" or \"x+=+%2824+-+0%29%2F%2818%29\" Break up the expression. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%2824%29%2F%2818%29\" or \"x+=++%2824%29%2F%2818%29\" Combine like terms. \r
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\n" ); document.write( "\n" ); document.write( "\"x+=+4%2F3\" or \"x+=+4%2F3\" Simplify. \r
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\n" ); document.write( "\n" ); document.write( "So our answer is \"x+=+4%2F3\" (with a multiplicity of 2)\r
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\n" ); document.write( "\n" ); document.write( "Option # 2 Factoring:\r
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\n" ); document.write( "\n" ); document.write( "\"9x%5E2-24x%2B16=0\" Start with the given equation\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-4%29%283x-4%29=0\" Factor the left side (note: if you need help with factoring, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Now set each factor equal to zero:\r
\n" ); document.write( "\n" ); document.write( "\"3x-4=0\" or \"3x-4=0\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=4%2F3\" or \"x=4%2F3\" Now solve for x in each case\r
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\n" ); document.write( "\n" ); document.write( "Since we have a repeating answer, our only answer is \"x=4%2F3\"\r
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