document.write( "Question 151453: sqrt(t+12)-t=0 is the problem. solve algebraically and check potential solutions\r
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document.write( "I'm not sure whether to add t+12 then square or distribute after t^2+12^2-t=0 \n" );
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Algebra.Com's Answer #111326 by oscargut(2103)![]() ![]() You can put this solution on YOUR website! sqrt(t+12)-t=0 \n" ); document.write( "then\r \n" ); document.write( "\n" ); document.write( "sqrt(t+12)=t \n" ); document.write( "then\r \n" ); document.write( "\n" ); document.write( "t+12=t^2 \n" ); document.write( "t^2-t-12=0 \n" ); document.write( "then\r \n" ); document.write( "\n" ); document.write( "t= (1+7)/2 or t= (1-7)/2 \n" ); document.write( "then t=4 or t=-3 (potential solutions) \n" ); document.write( "if t=4 \n" ); document.write( "sqrt(4+12)-4=sqrt(16)-4=0 (4 is a solution) \n" ); document.write( "if t=-3 \n" ); document.write( "sqrt(-3+12)-(-3)=sqrt(9)+3=6 (-3 is not a solution)\r \n" ); document.write( "\n" ); document.write( "Solution : t=4\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |