document.write( "Question 151399: Sandy has $3.75 in change. She has three more quarters than dimes but twice as many nickels as quarters. Express the given information as an algebraic expression and simplify. \n" ); document.write( "
Algebra.Com's Answer #111292 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Sandy has $3.75 in change. She has three more quarters than dimes but twice as many nickels as quarters. Express the given information as an algebraic expression and simplify.
\n" ); document.write( ":
\n" ); document.write( "\"Sandy has $3.75 in change.\"
\n" ); document.write( ".05n + .10d + .25q = 3.75
\n" ); document.write( ":
\n" ); document.write( "\" She has three more quarters than dimes\"
\n" ); document.write( "q = d + 3
\n" ); document.write( "or
\n" ); document.write( "d = (q-3)
\n" ); document.write( ":
\n" ); document.write( "\" but twice as many nickels as quarters.\"
\n" ); document.write( "n = 2q
\n" ); document.write( ":
\n" ); document.write( " Express the given information as an algebraic expression and simplify.
\n" ); document.write( ";
\n" ); document.write( ".05n + .10d + .25q = 3.75
\n" ); document.write( ":
\n" ); document.write( "Substitute for n and d, and you have:
\n" ); document.write( ".05(2q) + .10(q-3) + .25q = 375
\n" ); document.write( ":
\n" ); document.write( ".10q + .10q - .3 + .25q = 3.75
\n" ); document.write( ":
\n" ); document.write( ".45q = 3.75 + .3
\n" ); document.write( ":
\n" ); document.write( ".45q = 4.05
\n" ); document.write( "q = \"4.05%2F.45\"
\n" ); document.write( "q = 9 quarters
\n" ); document.write( ":
\n" ); document.write( "It's a simple matter to find n and d:
\n" ); document.write( "
\n" ); document.write( "
\n" );