document.write( "Question 151399: Sandy has $3.75 in change. She has three more quarters than dimes but twice as many nickels as quarters. Express the given information as an algebraic expression and simplify. \n" ); document.write( "
Algebra.Com's Answer #111292 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Sandy has $3.75 in change. She has three more quarters than dimes but twice as many nickels as quarters. Express the given information as an algebraic expression and simplify. \n" ); document.write( ": \n" ); document.write( "\"Sandy has $3.75 in change.\" \n" ); document.write( ".05n + .10d + .25q = 3.75 \n" ); document.write( ": \n" ); document.write( "\" She has three more quarters than dimes\" \n" ); document.write( "q = d + 3 \n" ); document.write( "or \n" ); document.write( "d = (q-3) \n" ); document.write( ": \n" ); document.write( "\" but twice as many nickels as quarters.\" \n" ); document.write( "n = 2q \n" ); document.write( ": \n" ); document.write( " Express the given information as an algebraic expression and simplify. \n" ); document.write( "; \n" ); document.write( ".05n + .10d + .25q = 3.75 \n" ); document.write( ": \n" ); document.write( "Substitute for n and d, and you have: \n" ); document.write( ".05(2q) + .10(q-3) + .25q = 375 \n" ); document.write( ": \n" ); document.write( ".10q + .10q - .3 + .25q = 3.75 \n" ); document.write( ": \n" ); document.write( ".45q = 3.75 + .3 \n" ); document.write( ": \n" ); document.write( ".45q = 4.05 \n" ); document.write( "q = \n" ); document.write( "q = 9 quarters \n" ); document.write( ": \n" ); document.write( "It's a simple matter to find n and d: \n" ); document.write( " \n" ); document.write( " |