document.write( "Question 151372: write the equation of y = 1/3x - 2 in standard form using only integers and a positive coefficient of x \n" ); document.write( "
Algebra.Com's Answer #111257 by jim_thompson5910(35256)\"\" \"About 
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\"y+=+%281%2F3%29x+-+2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"3y+=+3%28%281%2Fcross%283%29%29x+-+2%29\" Multiply both sides by 3 to eliminate the fractions.\r
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\n" ); document.write( "\n" ); document.write( "\"3y+=+x+-+6\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "\"3y-x=-6\" Subtract \"x\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-x%2B3y=-6\" Rearrange the terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-1%28-x%2B3y%29=-1%28-6%29\" Multiply both sides by -1. This will make the x coefficient positive.\r
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\n" ); document.write( "\n" ); document.write( "\"x-3y=6\" Distribute and multiply.\r
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\n" ); document.write( "\n" ); document.write( "So the equation is now in standard form \"Ax%2BBy=C\" where \"A=1\", \"B=-3\" and \"C=6\"
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