document.write( "Question 22746: Can someone PLEASE help me!!! What is the value of X in the equation:
\n" );
document.write( "logX = (1/2)log
25-5log
2 Thanks for all the help. By the way 1/2 is the fraction one half. \n" );
document.write( "
Algebra.Com's Answer #11125 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Moving everything to the left side of the equal sign you get: \n" ); document.write( "log x -(1/2)log 25 + 5log2 =0 (Note: all terms are base 3) \n" ); document.write( "Applying the laws of logs you get: \n" ); document.write( "log [x(2^5)/sqrt 25]=0 \n" ); document.write( "log [32x/5] = 0 (Remember the base is 3) \n" ); document.write( "Therefore: \n" ); document.write( "32x/5 = 3^0 \n" ); document.write( "32x = 5 \n" ); document.write( " x = 5/32\r \n" ); document.write( "\n" ); document.write( "This is only one way to do the problem. If you know \n" ); document.write( "your log laws you probably can figure out several other \n" ); document.write( "ways to get the same answer.\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |