document.write( "Question 22746: Can someone PLEASE help me!!! What is the value of X in the equation:
\n" ); document.write( "log\"3\"X = (1/2)log\"3\"25-5log\"3\"2 Thanks for all the help. By the way 1/2 is the fraction one half.
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Algebra.Com's Answer #11125 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Moving everything to the left side of the equal sign you get:
\n" ); document.write( "log x -(1/2)log 25 + 5log2 =0 (Note: all terms are base 3)
\n" ); document.write( "Applying the laws of logs you get:
\n" ); document.write( "log [x(2^5)/sqrt 25]=0
\n" ); document.write( "log [32x/5] = 0 (Remember the base is 3)
\n" ); document.write( "Therefore:
\n" ); document.write( "32x/5 = 3^0
\n" ); document.write( "32x = 5
\n" ); document.write( " x = 5/32\r
\n" ); document.write( "\n" ); document.write( "This is only one way to do the problem. If you know
\n" ); document.write( "your log laws you probably can figure out several other
\n" ); document.write( "ways to get the same answer.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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