document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=151342>Question 151342</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Could you help me solve for the ordered pairs?<BR>\n" );
document.write( "y=5^(3x+1)<BR>\n" );
document.write( "y=25^(-x) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111247 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y=25^(-x) __ y=(5^2)^(-x) __ y=5^(-2x)\r<BR>\n" );
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document.write( "substituting __ 5^(3x+1)=5^(-2x) __ 3x+1=-2x __ subtracting 3x __ 1=-5x __ dividing by -5 __ -1/5=x\r<BR>\n" );
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document.write( "substituting __ y=25^(1/5)  </SPAN>\n" );
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