document.write( "Question 151325: 5 square root of x + 1 = 3 \r
\n" ); document.write( "\n" ); document.write( "2/3 = 2 - 5x-3 over x-1 \r
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Algebra.Com's Answer #111241 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
I'll do the first one to get you started.\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Asqrt%28x%2B1%29=3\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%2B1%29=3%2F5\" Divide both sides by 5.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=%283%2F5%29%5E2\" Square both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B1=9%2F25\" Square \"3%2F5\" to get \"9%2F25\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=9%2F25-1\" Subtract 1 from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=-16%2F25\" Combine the fractions.\r
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\n" ); document.write( "\n" ); document.write( "So the solution is \"x=-16%2F25\" which approximates to \"x=-0.64\"
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