document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=150174>Question 150174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem!<BR>\n" );
document.write( "If we establish an identity, -sin A csc A - sin^2 A - cos^2 A - tan A cot A would equal which of the following:<BR>\n" );
document.write( "1. -2 + 2 sin^2 A<BR>\n" );
document.write( "2. -3<BR>\n" );
document.write( "3. 3 cos^2 A - 1<BR>\n" );
document.write( "4. 3 cos^2 A - 2 sin^2 A<BR>\n" );
document.write( "Thank you, Lennie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #111206 by </B><A HREF=/tutors/aboutme.mpl?userid=jojo14344><B>jojo14344(1513)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jojo14344><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=111206\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -sin A csc A - sin^2 A - cos^2 A - tan A cot A ---------> eqn 1<BR>\n" );
document.write( "Okay let's isolate section by section:<BR>\n" );
document.write( "1st part: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-sinAcscA ALIGN=MIDDLE  ALT=\"-sinAcscA\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "By reciprocal identities: <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sinA=1%2FcscA ALIGN=MIDDLE  ALT=\"sinA=1%2FcscA\"   DISABLED_style= \"max-width:90%; height:auto;\" >----------> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1=sinAcscA ALIGN=MIDDLE  ALT=\"1=sinAcscA\"   DISABLED_style= \"max-width:90%; height:auto;\" >, substitute in eqn 1 and looks:<BR>\n" );
document.write( "=-1-sin^2A-cos^2A-tanAcotA<BR>\n" );
document.write( "2nd part:<BR>\n" );
document.write( "-sin^2A-cos^2A <BR>\n" );
document.write( "By Pyth. identities:<BR>\n" );
document.write( "sin^2 A + cos^2 A=1, since it has (-) on the 2nd part, then it will be = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1 ALIGN=MIDDLE  ALT=\"-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( ".<BR>\n" );
document.write( "Eqn 1 becomes now,<BR>\n" );
document.write( "-1-1- tanA cotA<BR>\n" );
document.write( "By reciprocal identities: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tanA=1%2FcotA ALIGN=MIDDLE  ALT=\"tanA=1%2FcotA\"   DISABLED_style= \"max-width:90%; height:auto;\" > ----> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1=tanAcotA ALIGN=MIDDLE  ALT=\"1=tanAcotA\"   DISABLED_style= \"max-width:90%; height:auto;\" >, substituting<BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-1-1-1 ALIGN=MIDDLE  ALT=\"-1-1-1\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "= <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-3 ALIGN=MIDDLE  ALT=\"-3\"   DISABLED_style= \"max-width:90%; height:auto;\" > --------------------> FINAL ANSWER <font size=5><b>no.2</font><BR>\n" );
document.write( "Thank you,<BR>\n" );
document.write( "Jojo<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );