document.write( "Question 151150: Each of the three dimensions of a cube with a volume of y3 cubic centimeters is decreased by a whole number of centimeters. If the new volume is y3 - 13y2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height? \n" ); document.write( "
Algebra.Com's Answer #111116 by ankor@dixie-net.com(22740)\"\" \"About 
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Each of the three dimensions of a cube with a volume of y^3 cubic centimeters is decreased by a whole number of centimeters.
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\n" ); document.write( "If the new volume is y^3 - 13y^2 + 54y - 72 cubic centimeters and the new width is y-6 centimeters, then what are the new length and height?
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\n" ); document.write( "Use synthetic division, divide the vol by the width
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\n" ); document.write( " 6 | 1 - 13 + 54 - 72
\n" ); document.write( "............+6 - 42 + 72
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\n" ); document.write( ".......1 - 7 + 12 + 0
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\n" ); document.write( "The quotient: y^2 - 7y + 12
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\n" ); document.write( "Which factors to (y-4)(y-3)
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\n" ); document.write( "The new length = +4, new height = +3
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\n" ); document.write( "You can check solution: (y-6)*(y-4)*(y-3)\r
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