document.write( "Question 149422: If we establish an identity:
\n" ); document.write( "(tan A - cot A/tan A + cot A) would equal what? \n" ); document.write( "

Algebra.Com's Answer #111112 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
Re-writing,
\n" ); document.write( " $\"%28tanA-cotA%29%2F%28tanA%2BcotA%29\"$
\n" ); document.write( "By quotient identities:
\n" ); document.write( "= $\"%28%28sinA%2FcosA%29-%28cosA%2FsinA%29%29%2F%28%28sinA%2FcosA%29%2B%28cosA%2FsinA%29%29\"$
\n" ); document.write( "=

\n" ); document.write( "= $\"%28sin%5E2%28A%29-cos%5E2%28A%29%29%2F%28sin%5E2%28A%29%2Bcos%5E2%28A%29%29\"$ = $\"%28sin%5E2%28A%29-cos%5E2%28A%29%29%2F1\"$ -->A
\n" ); document.write( "We have to remember the identity for \"double angle formulas\":
\n" ); document.write( " $\"cos2%28mu%29=cos%5E2%28mu%29-sin%5E2%28mu%29\"$ --------------> B
\n" ); document.write( "*note\" $\"%28mu%29=A\"$
\n" ); document.write( "So,
\n" ); document.write( "= $\"-cos2A\"$ , FINAL ANSWER ----> see the negative (-) sign, bec. the final answer $\"A\"$ is opposite the identity $\"B\"$ .
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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