document.write( "Question 151185: if the first and third of three consecutive odd integers are added, the result is 63 less than five times the second integer. Find the third integer. \n" ); document.write( "
Algebra.Com's Answer #111101 by mangopeeler07(462)\"\" \"About 
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x=first consecutive odd
\n" ); document.write( "x+2=second consecutive odd
\n" ); document.write( "x+4=third consecutive odd\r
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\n" ); document.write( "\n" ); document.write( "first + third= 5(second)-63\r
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\n" ); document.write( "\n" ); document.write( "Plug in the variables
\n" ); document.write( "x+(x+4)=5(x+2)-63\r
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\n" ); document.write( "\n" ); document.write( "Distribute
\n" ); document.write( "x+x+4=5x+10-63\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms on both sides
\n" ); document.write( "2x+4=5x-53\r
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\n" ); document.write( "\n" ); document.write( "Add 53 to both sides
\n" ); document.write( "2x+57=5x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Subtract 2x from both sides
\n" ); document.write( "57=3x\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 3
\n" ); document.write( "19=x\r
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\n" ); document.write( "\n" ); document.write( "first consecutive odd=(19)
\n" ); document.write( "second consecutive odd=(19)+2
\n" ); document.write( "third consecutive odd=(19)+4
\n" ); document.write( "------------------------------------------------------------------------
\n" ); document.write( "Answer:
\n" ); document.write( "first consecutive odd=19
\n" ); document.write( "second consecutive odd=21
\n" ); document.write( "**third consecutive odd=23**
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