document.write( "Question 151185: if the first and third of three consecutive odd integers are added, the result is 63 less than five times the second integer. Find the third integer. \n" ); document.write( "
Algebra.Com's Answer #111101 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! x=first consecutive odd \n" ); document.write( "x+2=second consecutive odd \n" ); document.write( "x+4=third consecutive odd\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first + third= 5(second)-63\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Plug in the variables \n" ); document.write( "x+(x+4)=5(x+2)-63\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Distribute \n" ); document.write( "x+x+4=5x+10-63\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Combine like terms on both sides \n" ); document.write( "2x+4=5x-53\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 53 to both sides \n" ); document.write( "2x+57=5x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtract 2x from both sides \n" ); document.write( "57=3x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Divide both sides by 3 \n" ); document.write( "19=x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "first consecutive odd=(19) \n" ); document.write( "second consecutive odd=(19)+2 \n" ); document.write( "third consecutive odd=(19)+4 \n" ); document.write( "------------------------------------------------------------------------ \n" ); document.write( "Answer: \n" ); document.write( "first consecutive odd=19 \n" ); document.write( "second consecutive odd=21 \n" ); document.write( "**third consecutive odd=23** \n" ); document.write( " |